PARAGRAPH (IIT JEE 2007): The figure shows a surface XY separating two transparent media, medium-1 and medium-2. The lines ab and cd represent wavefronts of a light wave travelling in medium-1 and incident on XY. The lines ef and gh represents wavefronts of the light wave in medium-2 after refraction.
Question 1: Light travels as a,
Solution: The wavefronts in medium 1 are parallel to each other. Hence incident beam consists of parallel light rays. Same is true for refracted beam in the medium 2. Thus, A is correct.
Question 2: The phases of the light wave at c, d, e and f are $\phi_c$, $\phi_d$, $\phi_e$ and $\phi_f$ respectively. It is given that $\phi_c\neq \phi_f$.}
Solution: By definition, the phase at all points on a wavefront is equal. Thus, $\phi_c=\phi_d$ and $\phi_e=\phi_f$. Hence, $(\phi_d-\phi_f)=(\phi_c-\phi_e)$. Also, since $\phi_c\neq\phi_f$, we get $(\phi_c=\phi_d)\neq (\phi_e=\phi_f)$. Thus C is correct option.
Question 3: Speed of light is,
Solution: The ray of light travels normal to the wavefront. The ray bends towards the normal while going from medium 1 to medium 2. Hence, by Snell's law, medium 2 is denser than medium 1 i.e., $\mu_2 > \mu_1$. Thus, $v_2 = c/\mu_2 < c/\mu_1 = v_1$ i.e., speed of light is larger in medium 1. Thus B is correct choice.